21. Nilai dari Lim (√9x² + 4x + 2 3x +1)=... x → 00 A.5/3 B.5/2 C.1/3 D.-1/3 E. -5/3 2
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Jawaban:
A. 5/3
Penjelasan dengan langkah-langkah:
[tex] \lim_{x \to \infty } \sqrt{9 {x}^{2} + 4x + 2} - 3x + 1 \\ = \lim_{x \to \infty } \sqrt{9 {x}^{2} + 4x + 2} - ( 3x - 1) \\ = \lim_{x \to \infty } \sqrt{9 {x}^{2} + 4x + 2} - ( \sqrt{ (3x - 1) {}^{2} } ) \\ = \lim_{x \to \infty } \sqrt{9 {x}^{2} + 4x + 2} - \sqrt{9 {x}^{2} -6x + 1} \\ = \frac{b - q}{2 \sqrt{a} } \\ = \frac{4 - (-6)}{2 \sqrt{9} } \\ = \frac{ 10}{2(3)} = \frac{ 10}{6} \\ = \frac{5}{3} [/tex]
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